Matematika Faktorisasi aljabar dari1. (3y+2) (5y+3)2. (2a+3)²3. (2y-3)²4. (2y-2) (3y+2)5. (3y-2) (2y-2)TOLONG DIBANTU KAK PAKE CARA...#helpme#saveme​

colemanbreitenbergulv – April 07, 2023

Faktorisasi aljabar dari
1. (3y+2) (5y+3)
2. (2a+3)²
3. (2y-3)²
4. (2y-2) (3y+2)
5. (3y-2) (2y-2)


TOLONG DIBANTU KAK PAKE CARA...

#helpme
#saveme​

Penjelasan dengan langkah-langkah:

1. (3y+2) (5y+3)

menggunakan sifat distributif

= 3y×5y+3y×3 + 2×5y+2×3

= 15y²+9y+10y+6

= 15y²+19y+6

2. (2a+3)²

= (2a+3) (2a+3)

= 2a.2a+2a.3+3.2a+3.3

= 4a²+6a+6a+9

= 4a²+12a+9

3. (2y-3)²

= (2y-3) (2y-3)

= 2y.2y+2y.(-3)+(-3).2y+(-3).(-3)

= 4y²-6y-6y+9

= 4y²-12y+9

4. (2y-2) (3y+2)

= 2y.3y + 2y.2 + (-2).3y + (-2)×2

= 6y²+4y-6y-4

= 6y²-2y-4

5. (3y-2) (2y-2)

= 3y.2y+3y.(-2)+(-2).2y+(-2).(-2)

= 6y²-6y-4y+4

= 6y²-10y+4

maaf kalo salah

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